%I #4 Mar 30 2012 18:56:21
%S 1,1,1,2,1,2,2,2,2,2,3,4,5,5,5,6,5,5,5,5,6,5,5,5,6,6,7,7,7,6,5,5,5,5,
%T 5,4,5,5,5,5,5,5,5,5,5,5,5,4,4,5,5,6,7,7,7,8,9,9,8,8,7,7,6,6,6,6,6,6,
%U 7,8,7,7,8,8,8,9,10,10,9,9,10,11,11,11,11,11
%N a(n)=(# 1's)-(# 0's) in first n terms of A031269.
%K nonn
%O 1,4
%A _Clark Kimberling_
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