The OEIS mourns the passing of Jim Simons and is grateful to the Simons Foundation for its support of research in many branches of science, including the OEIS.
login
The OEIS is supported by the many generous donors to the OEIS Foundation.

 

Logo
Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A365327 Triangle read by rows: T(n,k) is the number of spanning subgraphs of the n-cycle graph with domination number k. 1
2, 3, 1, 4, 3, 1, 0, 11, 4, 1, 0, 11, 15, 5, 1, 0, 10, 26, 21, 6, 1, 0, 0, 43, 49, 28, 7, 1, 0, 0, 33, 98, 80, 36, 8, 1, 0, 0, 22, 126, 189, 120, 45, 9, 1, 0, 0, 0, 141, 322, 325, 170, 55, 10, 1, 0, 0, 0, 89, 462, 671, 517, 231, 66, 11, 1, 0, 0, 0, 46, 480, 1162, 1236, 777, 304, 78, 12, 1, 0, 0, 0, 0, 417, 1586, 2483, 2093, 1118, 390, 91, 13, 1 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
For n >= 3 the n-cycle graph is a simple graph. In the case of n=1 the graph is a loop and for n=2 a double edge.
The number of spanning subgraphs of the n-cycle graph is given by 2^n which is also the sum of the n-th row Sum_{k=1..n} T(n,k).
The average domination number is given by (Sum_{k=1..n} k*T(n,k))/2^n.
The relative average domination number is given by ((Sum_{k=1..n} k*T(n,k))/2^n)/n.
LINKS
Roman Hros, Effective Enumeration of Selected Graph Characteristics, IIT.SRC 2020: 16th Student Research Conference in Informatics and Information Technologies.
FORMULA
T(n,n) = 1 for n > 1.
T(n,n-1) = T(n-1, n-2) + 1 for n > 3.
T(n,n-2) = T(n-1, n-3) + T(n, n-1) for n > 5.
T(n,n-3) = T(n-1, n-4) + T(n, n-2) - 5 for n > 6.
T(n,n-4) = T(n-1, n-5) + T(n-1, n-4) + 11 + Sum_{i=1..n-9} (i+4) for n > 8.
G.f.:
For n > 3; G(n) = x*(G(n-1) + G(n-2) + 2*G(n-3)) + g(n); where
2*(1-x)*x^(n/3) for n mod 3 = 0.
g(n) = { 0 for n mod 3 = 1.
(1-x)*x^((n+1)/3) for n mod 3 = 2.
For n mod 3 = 0:
T(n,k) = 2*T(n-3,k-1) + T(n-2,k-1) + T(n-1,k-1) + 2 for k = n/3.
T(n,k) = 2*T(n-3,k-1) + T(n-2,k-1) + T(n-1,k-1) - 2 for k = n/3 + 1.
T(n,k) = 2*T(n-3,k-1) + T(n-2,k-1) + T(n-1,k-1) for k >= n/3 + 2.
For n mod 3 = 1:
T(n,k) = 2*T(n-3,k-1) + T(n-2,k-1) + T(n-1,k-1) for k >= (n+2)/3.
For n mod 3 = 2:
T(n,k) = 2*T(n-3,k-1) + T(n-2,k-1) + T(n-1,k-1) + 1 for k = (n+1)/3.
T(n,k) = 2*T(n-3,k-1) + T(n-2,k-1) + T(n-1,k-1) - 1 for k = (n+1)/3 + 1.
T(n,k) = 2*T(n-3,k-1) + T(n-2,k-1) + T(n-1,k-1) for k >= (n+1)/3 + 2.
EXAMPLE
Example of spanning subgraphs of cycle with 2 vertices:
Domination number: 2 1 1 1
/\ /\
. . . . . . . .
\/ \/
The triangle T(n,k) begins:
n\k 1 2 3 4 5 6 7 8 9 10 11 12 ...
1: 2
2: 3 1
3: 4 3 1
4: 0 11 4 1
5: 0 11 15 5 1
6: 0 10 26 21 6 1
7: 0 0 43 49 28 7 1
8: 0 0 33 98 80 36 8 1
9: 0 0 22 126 189 120 45 9 1
10: 0 0 0 141 322 325 170 55 10 1
11: 0 0 0 89 462 671 517 231 66 11 1
12: 0 0 0 46 480 1162 1236 777 304 78 12 1
CROSSREFS
Row sums are A000079.
Column sums are A002063(k-1).
Sequence in context: A120873 A125161 A331791 * A125933 A255054 A011857
KEYWORD
nonn,tabl
AUTHOR
Roman Hros, Sep 01 2023
STATUS
approved

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recents
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified May 23 11:57 EDT 2024. Contains 372763 sequences. (Running on oeis4.)