A353542 a(n) is the least start of a run of n consecutive numbers whose abundancy index is larger than Pi^2/6.

4, 44, 188, 8110374, 330921744

Offset

1,1

Comments

By the Chinese Remainder Theorem, a(n) exists for all n. The proof is similar to the proof that is given for A094268.

Links

Table of n, a(n) for n=1..5.

Example

a(1) = 4 since 4 is the least term of A353537.
a(2) = 44 since 44 is the least term of A353538.

Crossrefs

Cf. A000203, A013661, A094268.

Cf. A353537, A353538, A353539, A353540, A353541.

Sequence in context: A053314 A051223 A330651 * A265081 A077435 A271294

Adjacent sequences: A353539 A353540 A353541 * A353543 A353544 A353545

Keyword

nonn,more

Author

Amiram Eldar, Apr 25 2022

Status

approved