%I #7 Aug 05 2021 15:22:28
%S 955,969,1046,1053,1072,1079,1107,1117,1121,1158,1161,1170,1177,1184,
%T 1196,1198,1216,1222,1235,1242,1254,1261,1268,1272,1280,1287,1291,
%U 1294,1297,1298,1305,1310,1324,1350,1351,1355,1366,1369,1376,1378,1385,1388,1392
%N Numbers that are the sum of seven cubes in six or more ways.
%H Sean A. Irvine, <a href="/A345524/b345524.txt">Table of n, a(n) for n = 1..10000</a>
%e 969 is a term because 969 = 1^3 + 1^3 + 1^3 + 3^3 + 5^3 + 6^3 + 6^3 = 1^3 + 2^3 + 2^3 + 2^3 + 5^3 + 5^3 + 7^3 = 1^3 + 4^3 + 4^3 + 4^3 + 4^3 + 4^3 + 6^3 = 2^3 + 2^3 + 2^3 + 3^3 + 3^3 + 4^3 + 8^3 = 2^3 + 3^3 + 4^3 + 4^3 + 4^3 + 5^3 + 6^3 = 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 6^3 + 6^3.
%o (Python)
%o from itertools import combinations_with_replacement as cwr
%o from collections import defaultdict
%o keep = defaultdict(lambda: 0)
%o power_terms = [x**3 for x in range(1, 1000)]
%o for pos in cwr(power_terms, 7):
%o tot = sum(pos)
%o keep[tot] += 1
%o rets = sorted([k for k, v in keep.items() if v >= 6])
%o for x in range(len(rets)):
%o print(rets[x])
%Y Cf. A345483, A345515, A345523, A345525, A345536, A345572, A345778.
%K nonn
%O 1,1
%A _David Consiglio, Jr._, Jun 20 2021
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