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A345222
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Number of divisors of n with a prime number of divisors.
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1
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0, 1, 1, 2, 1, 2, 1, 2, 2, 2, 1, 3, 1, 2, 2, 3, 1, 3, 1, 3, 2, 2, 1, 3, 2, 2, 2, 3, 1, 3, 1, 3, 2, 2, 2, 4, 1, 2, 2, 3, 1, 3, 1, 3, 3, 2, 1, 4, 2, 3, 2, 3, 1, 3, 2, 3, 2, 2, 1, 4, 1, 2, 3, 4, 2, 3, 1, 3, 2, 3, 1, 4, 1, 2, 3, 3, 2, 3, 1, 4, 3, 2, 1, 4, 2, 2, 2, 3, 1, 4, 2, 3, 2
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OFFSET
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1,4
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COMMENTS
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Number of divisors of n that are powers of primes with an exponent k such that k+1 is a prime. - Amiram Eldar, Oct 06 2023
Inverse Möbius transform of sequence b(1) = 0, b(n) = A355937(n) for n > 1, or equivalently, one less than the inverse Möbius transform of A355937. - Antti Karttunen, Oct 06 2023
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LINKS
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FORMULA
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a(n) = Sum_{d|n} c(tau(d)), where c(n) is the prime characteristic.
Additive with a(p^e) = primepi(e+1).
Sum_{k=1..n} a(k) ~ n * (log(n) + B + C), where B is Mertens's constant (A077761), and C = Sum_{k>=2} P(prime(k)-1) = 0.54756961912815344341..., where P(s) is the prime zeta function. (End)
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EXAMPLE
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a(12) = 3; The divisors of 12 are {1, 2, 3, 4, 6, 12} and the corresponding number of divisors of each of these numbers is {1, 2, 2, 3, 4, 6}. Thus, there are 3 divisors of 12 with a prime number of divisors.
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MATHEMATICA
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Table[Sum[(PrimePi[DivisorSigma[0, k]] - PrimePi[DivisorSigma[0, k] - 1]) (1 - Ceiling[n/k] + Floor[n/k]), {k, n}], {n, 100}]
f[p_, e_] := PrimePi[e+1]; a[1] = 0; a[n_] := Plus @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Oct 06 2023 *)
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PROG
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(PARI) a(n) = sumdiv(n, d, isprime(numdiv(d))); \\ Michel Marcus, Jun 11 2021
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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