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A340423 Irregular triangle read by rows T(n,k) in which row n has length A000041(n-1) and every column k is A024916, n >= 1, k >= 1. 6
1, 4, 8, 1, 15, 4, 1, 21, 8, 4, 1, 1, 33, 15, 8, 4, 4, 1, 1, 41, 21, 15, 8, 8, 4, 4, 1, 1, 1, 1, 56, 33, 21, 15, 15, 8, 8, 4, 4, 4, 4, 1, 1, 1, 1, 69, 41, 33, 21, 21, 15, 15, 8, 8, 8, 8, 4, 4, 4, 4, 1, 1, 1, 1, 1, 1, 1, 87, 56, 41, 33, 33, 21, 21, 15, 15, 15, 15, 8, 8, 8, 8 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
T(n,k) is the number of cubic cells (or cubes) in the k-th level starting from the base of the tower described in A221529 whose largest side of the base is equal to n (see example). - Omar E. Pol, Jan 08 2022
LINKS
FORMULA
T(n,k) = A024916(A336811(n,k)).
T(n,k) = Sum_{j=1..n} A339278(j,k). - Omar E. Pol, Jan 08 2022
EXAMPLE
Triangle begins:
1;
4;
8, 1;
15, 4, 1;
21, 8, 4, 1, 1;
33, 15, 8, 4, 4, 1, 1;
41, 21, 15, 8, 8, 4, 4, 1, 1, 1, 1;
56, 33, 21, 15, 15, 8, 8, 4, 4, 4, 4, 1, 1, 1, 1;
69, 41, 33, 21, 21, 15, 15, 8, 8, 8, 8, 4, 4, 4, 4, 1, 1, 1, 1, 1, 1, 1;
...
For n = 9 the length of row 9 is A000041(9-1) = 22.
From Omar E. Pol, Jan 08 2022: (Start)
For n = 9 the lateral view and top view of the tower described in A221529 look like as shown below:
_
22 1 | |
21 1 | |
20 1 | |
19 1 | |
18 1 | |
17 1 | |
16 1 |_|_
15 4 | |
14 4 | |
13 4 | |
12 4 |_ _|_
11 8 | | |
10 8 | | |
9 8 | | |
8 8 |_ _|_|_
7 15 | | |
6 15 |_ _ _| |_
5 21 | | |
4 21 |_ _ _|_ _|_
3 33 |_ _ _ _| | |_
2 41 |_ _ _ _|_|_ _|_ _
1 69 |_ _ _ _ _|_ _|_ _|
.
Level Row 9 Lateral view
k T(9,k) of the tower
.
_ _ _ _ _ _ _ _ _
|_| | | | | | | |
|_ _|_| | | | | |
|_ _| _|_| | | |
|_ _ _| _|_| |
|_ _ _| _| _ _|
|_ _ _ _| |
|_ _ _ _| _ _|
| |
|_ _ _ _ _|
.
Top view
of the tower
.
For n = 9 and k = 1 there are 69 cubic cells in the level 1 starting from the base of the tower, so T(9,1) = 69.
For n = 9 and k = 22 there is only one cubic cell in the level 22 (the top) of the tower, so T(9,22) = 1.
The volume of the tower (also the total number of cubic cells) represents the 9th term of the convolution of A000203 and A000041 hence it's equal to A066186(9) = 270, equaling the sum of the 9th row of triangle. (End)
PROG
(PARI) f(n) = numbpart(n-1);
T(n, k) = {if (k > f(n), error("invalid k")); if (k==1, return (n)); my(s=0); while (k <= f(n-1), s++; n--; ); 1+s; } \\ A336811
g(n) = sum(k=1, n, n\k*k); \\ A024916
row(n) = vector(f(n), k, g(T(n, k))); \\ Michel Marcus, Jan 22 2022
CROSSREFS
Row sums give A066186.
Row lengths give A000041.
The length of the m-th block in row n is A187219(m), m >= 1.
Cf. A350637 (analog for the stepped pyramid described in A245092).
Sequence in context: A294830 A248415 A328250 * A367416 A295086 A331331
KEYWORD
nonn,tabf
AUTHOR
Omar E. Pol, Jan 07 2021
STATUS
approved

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Last modified May 8 00:02 EDT 2024. Contains 372317 sequences. (Running on oeis4.)