The OEIS mourns the passing of Jim Simons and is grateful to the Simons Foundation for its support of research in many branches of science, including the OEIS.
login
The OEIS is supported by the many generous donors to the OEIS Foundation.

 

Logo
Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A339870 Composite numbers k of the form 4u+1 for which the odd part of phi(k) divides k-1. 9

%I #32 Feb 18 2021 00:50:09

%S 85,561,1105,1261,1285,2465,4369,6601,8245,8481,9061,9605,10585,16405,

%T 16705,17733,18721,19669,21845,23001,28645,30889,38165,42121,43165,

%U 46657,54741,56797,57205,62745,65365,74593,78013,83665,88561,91001,106141,117181,124645,126701,134521,136981,141661,162401,171205,176437

%N Composite numbers k of the form 4u+1 for which the odd part of phi(k) divides k-1.

%C From _Antti Karttunen_, Dec 26 2020: (Start)

%C Equally, squarefree composite numbers k of the form 4u+1 for which A336466(k) divides k-1. This follows because on squarefree n, A336466(n) = A053575(n).

%C No common terms with A016105, because 4xy + 2(x+y) + 1 does not divide 4xy + 3(x+y) + 2 for any distinct x, y >= 0 (where 4x+3 and 4y+3 are the two prime factors of Blum integers).

%C This can also seen by another way: If this sequence contained any Blum integers, then, because A016105 is a subsequence of A339817, we would have found a composite number n satisfying Lehmer's totient problem y * phi(n) = n-1, for some integer y > 1. But Lehmer proved that such solutions should have at least 7 distinct prime factors, while Blum integers have only two.

%C Moreover, it seems that none of the terms of A167181 may occur here, and a few of A137409 (i.e., of A125667). See A339875 for those terms.

%C (End)

%H Antti Karttunen, <a href="/A339870/b339870.txt">Table of n, a(n) for n = 1..1316</a>

%H D. H. Lehmer, <a href="http://dx.doi.org/10.1090/s0002-9904-1932-05521-5">On Euler's totient function</a>, Bulletin of the American Mathematical Society, 38 (1932), 745-751.

%H Wikipedia, <a href="https://en.wikipedia.org/wiki/Lehmer&#39;s_totient_problem">Lehmer's totient problem</a>

%e 85 = 4*21 + 1 = 5*17, thus phi(85) = 4*16 = 64, the odd part of which is A000265(64) = 1, which certainly divides 85-1, therefore 85 is included as a term.

%e 561 = 4*140 + 1 = 3*11*17, thus phi(561) = 2*10*16 = 320, the odd part of which is A000265(320) = 5, which divides 560, therefore 561 is included.

%t odd[n_] := n/2^IntegerExponent[n, 2]; Select[4*Range[45000] + 1, CompositeQ[#] && Divisible[# - 1, odd[EulerPhi[#]]] &] (* _Amiram Eldar_, Feb 17 2021 *)

%o (PARI)

%o A000265(n) = (n>>valuation(n, 2));

%o isA339870(n) = ((n>1)&&!isprime(n)&&(1==(n%4))&&!((n-1)%A000265(eulerphi(n))));

%Y Cf. A000010, A000265, A016105, A053575, A137409, A167181, A336466.

%Y Subsequence of A005117.

%Y Intersection of A091113 and A339880.

%Y Cf. A339875 (a subsequence).

%Y Cf. also comments in A339817.

%K nonn

%O 1,1

%A _Antti Karttunen_, Dec 22 2020

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recents
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified May 22 21:38 EDT 2024. Contains 372758 sequences. (Running on oeis4.)