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A338024
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Minimal number of moves for the cyclic variant of Hanoi's tower for 4 pegs and n disks, with the final peg one step away.
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2
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1, 6, 15, 28, 57, 98, 179, 304, 521, 894, 1519, 2576, 4381, 7434, 12603, 21380, 36265, 61486, 104263, 176808, 299797
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OFFSET
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1,2
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LINKS
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FORMULA
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Conjecture: a(n) = a(n-1) + a(n-2) + a(n-3) - 2*a(n-5) for n > 11.
Conjectured g.f.: x*(1+5*x+8*x^2+6*x^3+8*x^4+8*x^6-4*x^8+4*x^9-4*x^10)/((1-x)*(1+x)*(1-x-2*x^3)). - Stefano Spezia, Oct 07 2020 after Paul Zimmermann
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EXAMPLE
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For n=2, assume the two disks are on North initially, first move the smallest one to West in 3 moves, then the largest one to East in 1 move, and the smallest one to East also in 2 moves, with a total of 6 moves. Each disk has a number of moves which is 1 mod 4, thus a(n) = n mod 4.
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PROG
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(C++) See Martin Ehrenstein link, Oct 27 2020
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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