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A333369 Positive integers in which any odd digit, if present, occurs an odd number of times, and any even digit, if present, occurs an even number of times. 10
1, 3, 5, 7, 9, 13, 15, 17, 19, 22, 31, 35, 37, 39, 44, 51, 53, 57, 59, 66, 71, 73, 75, 79, 88, 91, 93, 95, 97, 100, 111, 122, 135, 137, 139, 144, 153, 157, 159, 166, 173, 175, 179, 188, 193, 195, 197, 212, 221, 223, 225, 227, 229, 232, 252, 272, 292, 300, 315, 317, 319, 322 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
Inspired by the 520th problem of Project Euler (see link) where such a number is called a "simber".
This sequence has little mathematical interest. The name "simber", which might be interpreted as "silly number", is deprecated. - N. J. A. Sloane, Aug 04 2022
The number of terms with respectively 1, 2, 3, ... digits is 5, 24, 130, ...
LINKS
Project Euler, Problem 520: Simbers.
EXAMPLE
656 is a 3-digit term because it has one 5 and two 6's.
447977 is a 6-digit term because it has one 9, two 4's and three 7's.
MATHEMATICA
seqQ[n_] := AllTrue[Tally @ IntegerDigits[n], EvenQ[Plus @@ #] &]; Select[Range[300], seqQ] (* Amiram Eldar, Mar 17 2020 *)
PROG
(PARI) isok(m) = my(d=digits(m), s=Set(d)); for (i=1, #s, if (#select(x->(x==s[i]), d) % 2 != (s[i] % 2), return (0))); return (1); \\ Michel Marcus, Mar 17 2020
(Python)
def ok(n): s = str(n); return all(s.count(d)%2 == int(d)%2 for d in set(s))
print([k for k in range(323) if ok(k)]) # Michael S. Branicky, Apr 15 2022
CROSSREFS
Cf. A108571 (finite subsequence), A353007.
Sequence in context: A029740 A063425 A215806 * A064608 A024893 A337810
KEYWORD
nonn,base
AUTHOR
Bernard Schott, Mar 17 2020
STATUS
approved

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Last modified May 2 08:27 EDT 2024. Contains 372178 sequences. (Running on oeis4.)