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A329294
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Numbers whose digits are in nondecreasing order in bases 4 and 5.
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6
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OFFSET
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1,3
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COMMENTS
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There are no more terms through 10^10000 (which is a 16610-digit number in base 4 and a 14307-digit number in base 5). But can it be proved that 343 is the final term of the sequence?
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LINKS
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EXAMPLE
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a(1) = 0 = 0_4 = 0_5
a(2) = 1 = 1_4 = 1_5
a(3) = 2 = 2_4 = 2_5
a(4) = 3 = 3_4 = 3_5
a(5) = 6 = 12_4 = 11_5
a(6) = 7 = 13_4 = 12_5
a(7) = 31 = 133_4 = 111_5
a(8) = 43 = 223_4 = 133_5
a(9) = 63 = 333_4 = 223_5
a(10) = 343 = 11113_4 = 2333_5
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PROG
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(PARI) isnondec(v) = (#v==0) || (#select(x->(x<0), vector(#v-1, k, v[k+1]-v[k])) == 0);
isok(n) = isnondec(digits(n, 4)) && isnondec(digits(n, 5)); \\ Michel Marcus, Nov 11 2019
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CROSSREFS
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Numbers whose digits are in nondecreasing order in bases b and b+1: this sequence (b=4), A329295 (b=5), A329296 (b=6), A329297 (b=7), A329298 (b=8), A329299 (b=9). See A329300 for the (apparently) largest term of each of these sequences.
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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