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%I #13 Oct 07 2019 18:44:29
%S 1,2,3,3,2,5,2,4,5,3,7,7,8,3,5,5,3,7,8,4,3,10,11,9,10,11,3,4,13,7,3,6,
%T 7,4,3,9,10,11,3,5,11,4,13,13,7,15,16,11,4,13,7,14,15,4,17,5,4,17,18,
%U 9,19,4,7,7,4,9,10,5,11,4,13,11,4,13,7,14,15,4
%N Numerator of the average position of a 1 in the reversed binary expansion of n.
%H Robert Israel, <a href="/A326699/b326699.txt">Table of n, a(n) for n = 1..10000</a>
%e The sequence of fractions begins: 1, 2, 3/2, 3, 2, 5/2, 2, 4, 5/2, 3, 7/3, 7/2, 8/3, 3, 5/2, 5, 3, 7/2, 8/3, 4.
%e For example, the reversed binary expansion of 18 is (0,1,0,0,1), and the average of {2,5} is 7/2, so a(18) = 7.
%p f:= proc(n) local L;
%p L:= convert(n,base,2);
%p L:= select(t -> L[t]=1, [$1..nops(L)]);
%p numer(convert(L,`+`)/nops(L))
%p end proc:
%p map(f, [$1..100]); # _Robert Israel_, Oct 07 2019
%t Table[Numerator[Mean[Join@@Position[Reverse[IntegerDigits[n,2]],1]]],{n,100}]
%Y Cf. A000120, A029931, A035327, A048793, A070939, A291166, A295235, A326669, A326674, A326700 (denominators).
%K nonn,frac,look
%O 1,2
%A _Gus Wiseman_, Jul 20 2019
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