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A324564
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Number T(n,k) of permutations p of [n] such that n-k is the maximum of 0 and the number of elements in any integer interval [p(i)..i+n*[i<p(i)]]; triangle T(n,k), n>=0, 0<=k<=n, read by rows.
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13
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1, 1, 0, 1, 1, 0, 4, 1, 1, 0, 15, 7, 1, 1, 0, 76, 31, 11, 1, 1, 0, 455, 185, 60, 18, 1, 1, 0, 3186, 1275, 435, 113, 29, 1, 1, 0, 25487, 10095, 3473, 1001, 215, 47, 1, 1, 0, 229384, 90109, 31315, 9289, 2299, 406, 76, 1, 1, 0, 2293839, 895169, 313227, 95747, 24610, 5320, 763, 123, 1, 1, 0
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OFFSET
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0,7
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COMMENTS
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LINKS
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EXAMPLE
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Triangle T(n,k) begins:
1;
1, 0;
1, 1, 0;
4, 1, 1, 0;
15, 7, 1, 1, 0;
76, 31, 11, 1, 1, 0;
455, 185, 60, 18, 1, 1, 0;
3186, 1275, 435, 113, 29, 1, 1, 0;
25487, 10095, 3473, 1001, 215, 47, 1, 1, 0;
...
Square array A(n,k) begins:
1, 0, 0, 0, 0, 0, ...
1, 1, 1, 1, 1, 1, ...
1, 1, 1, 1, 1, 1, ...
4, 7, 11, 18, 29, 47, ...
15, 31, 60, 113, 215, 406, ...
76, 185, 435, 1001, 2299, 5320, ...
455, 1275, 3473, 9289, 24610, 65209, ...
3186, 10095, 31315, 95747, 290203, 876865, ...
...
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MAPLE
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b:= proc(n, k) option remember; `if`(k>n, 0, `if`(k=0, n!,
LinearAlgebra[Permanent](Matrix(n, (i, j)->
`if`(j>=i and k+j<n+i or i>k+j, 1, 0)))))
end:
# as triangle:
T:= (n, k)-> b(n, k)-b(n, k+1):
seq(seq(T(n, k), k=0..n), n=0..10);
# as array:
A:= (n, k)-> b(n+k, k)-b(n+k, k+1):
seq(seq(A(d-k, k), k=0..d), d=0..10);
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MATHEMATICA
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b[n_, k_] := b[n, k] = If[k > n, 0, If[k == 0, n!, Permanent[Table[If[j >= i && k+j < n+i || i > k+j, 1, 0], {i, n}, {j, n}]]]];
(* as triangle: *)
T[n_, k_] := b[n, k] - b[n, k+1];
Table[T[n, k], {n, 0, 10}, {k, 0, n}] // Flatten
(* as array: *)
A[n_, k_] := b[n+k, k] - b[n+k, k+1];
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CROSSREFS
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Columns k=0-10 give: A002467 (for n>0), A324621, A324622, A324623, A324624, A324625, A324626, A324627, A324628, A324629, A324630.
Diagonals of the triangle (rows of the array) n=0, (1+2), 3-10 give: A000007, A000012, A000032 (for n>=3), A324631, A324632, A324633, A324634, A324635, A324636, A324637.
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KEYWORD
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AUTHOR
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STATUS
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approved
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