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A302906
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a(0) = 0; for n > 0, a(n) = a(n-1) + 5*n + 4.
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2
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0, 9, 23, 42, 66, 95, 129, 168, 212, 261, 315, 374, 438, 507, 581, 660, 744, 833, 927, 1026, 1130, 1239, 1353, 1472, 1596, 1725, 1859, 1998, 2142, 2291, 2445, 2604, 2768, 2937, 3111, 3290, 3474, 3663, 3857, 4056, 4260, 4469, 4683, 4902, 5126, 5355, 5589
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OFFSET
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0,2
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COMMENTS
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In A302717, if we count the terms added from each 4-tuple during each iteration we find that either two or three terms are added: 2, 2, 2, 3, 2, 2, 2, 3, 2, 3, 2, 2, 2, 3, ... where the set of three twos (2, 2, 2) appears with decreasing frequency. a(n) is the index into A302717 where each such set begins.
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LINKS
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FORMULA
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G.f.: x*(9 - 4*x)/(1 - x)^3.
a(n) = n*(5*n + 13)/2.
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n>2. (End)
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EXAMPLE
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with a=9 and b=10, a(20,21,22) are appended;
with a=10 and b=11, a(23,24) are appended;
with a=11 and b=12, a(25,26) are appended;
with a=12 and b=13, a(27,28) are appended;
with a=13 and b=14, a(29,30,31) are appended, so a(2) = 23, because A302717(23) is the start of three consecutively added pairs of terms.
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MATHEMATICA
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PROG
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(PARI) concat(0, Vec(x*(9 - 4*x) / (1 - x)^3 + O(x^50))) \\ Colin Barker, Apr 16 2018
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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