%I #20 Jan 11 2020 15:57:47
%S 2,4,7,8,9,5
%N Decimal expansion of the molar volume of a perfect gas in standard conditions in cubic meters per mole.
%C For a perfect gas we know Vm = RT/p. Where p is the pressure, Vm is the molar volume, T is the temperature and R is the molar gas constant. We will use the value of R according to NIST.
%C In standard conditions T = 298.15 K, p = 100000 Pa therefore:
%C Vm = A070064 J mol^-1 K^-1 * 298.15 K / 100000 Pa = 0.024789561 (14) m^3 mol^-1.
%C The number (14) denotes the current uncertainty of the value.
%H NIST, <a href="https://physics.nist.gov/cgi-bin/cuu/Value?r">Molar Gas Constant</a>
%H Wikipedia, <a href="https://en.wikipedia.org/wiki/Molar_volume">Molar Volume</a>.
%F Vm = A070064 * 0.0029815.
%F Vm = 0.024789561 (14) m^3 mol^-1.
%Y Cf. A070064.
%K nonn,cons,more
%O 1,1
%A _Natan Arie Consigli_, Mar 28 2018
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