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A284117 Sum of proper prime power divisors of n. 3

%I #17 Apr 01 2017 07:28:43

%S 0,0,0,4,0,0,0,12,9,0,0,4,0,0,0,28,0,9,0,4,0,0,0,12,25,0,36,4,0,0,0,

%T 60,0,0,0,13,0,0,0,12,0,0,0,4,9,0,0,28,49,25,0,4,0,36,0,12,0,0,0,4,0,

%U 0,9,124,0,0,0,4,0,0,0,21,0,0,25,4,0,0,0,28,117,0,0,4,0,0,0,12,0,9,0,4,0,0,0,60,0,49,9,29

%N Sum of proper prime power divisors of n.

%H Robert Israel, <a href="/A284117/b284117.txt">Table of n, a(n) for n = 1..10000</a>

%H <a href="/index/Su#sums_of_divisors">Index entries for sequences related to sums of divisors</a>

%F G.f.: Sum_{p prime, k>=2} p^k*x^(p^k)/(1 - x^(p^k)).

%F a(n) = Sum_{d|n, d = p^k, p prime, k >= 2} d.

%F a(n) = 0 if n is a squarefree (A005117).

%e a(8) = 12 because 12 has 6 divisors {1, 2, 3, 4, 6, 12} among which 2 are proper prime powers {4, 8} therefore 4 + 8 = 12.

%p f:= n -> add(t[1]*(t[1]^t[2]-t[1])/(t[1]-1), t=ifactors(n)[2]):

%p map(f, [$1..100]); # _Robert Israel_, Mar 31 2017

%t nmax = 100; Rest[CoefficientList[Series[Sum[Boole[PrimePowerQ[k] && PrimeOmega[k] > 1] k x^k/(1 - x^k), {k, 1, nmax}], {x, 0, nmax}], x]]

%t Table[Total[Select[Divisors[n], PrimePowerQ[#1] && PrimeOmega[#1] > 1 &]], {n, 100}]

%o (PARI) concat([0, 0, 0], Vec(sum(k=1, 100, (isprimepower(k) && bigomega(k)>1) * k * x^k/(1 - x^k)) + O(x^101))) \\ _Indranil Ghosh_, Mar 21 2017

%o (PARI) a(n) = sumdiv(n, d, d*(isprimepower(d) && !isprime(d))); \\ _Michel Marcus_, Apr 01 2017

%Y Cf. A001414, A008472, A023888, A023889, A046660, A246547.

%K nonn

%O 1,4

%A _Ilya Gutkovskiy_, Mar 20 2017

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