|
|
A270875
|
|
Number of subsets of {1,...,n} with sum of elements equal to least common multiple of elements and at least two elements.
|
|
1
|
|
|
0, 0, 1, 1, 1, 2, 2, 3, 5, 6, 6, 9, 9, 10, 13, 15, 15, 19, 19, 33, 35, 35, 35, 47, 47, 47, 50, 57, 57, 101, 101, 106, 108, 108, 108, 127, 127, 127, 128, 249, 249, 268, 268, 272, 358, 358, 358, 406, 406, 408, 409, 411, 411, 424, 424, 501, 502, 502, 502, 1190, 1190
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,6
|
|
COMMENTS
|
It appears that the sequence of n for which a(n)>a(n-1) has a large overlap with A175904.
|
|
LINKS
|
|
|
FORMULA
|
|
|
EXAMPLE
|
For n=3, the subsets of {1,2,3} with at least two elements have (sum,LCM) as follows: {1,2}->(3,2), {1,3}->(4,3), {2,3}->(5,6), {1,2,3}->(6,6). Only the last satisfies sum=LCM, so a(3)=1.
|
|
MATHEMATICA
|
Table[Length[Transpose@ {Total /@ #, LCM @@@ #} /. {a_, b_} /; a != b -> Nothing &@ Rest[Subsets[Range@ n] /. {_} -> Nothing]], {n, 2, 22}] (* Michael De Vlieger, Mar 24 2016 *)
|
|
PROG
|
(PARI) a(n) = {nb = 0; S = vector(n, k, k); for (i = 0, 2^n - 1, ss = vecextract(S, i); if (vecsum(ss) == lcm(ss), nb++); ); nb - n; } \\ Michel Marcus, Mar 26 2016
|
|
CROSSREFS
|
Cf. A270970 (similar sequence counting trivial solutions).
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|