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A265525 a(n) = largest base-10 palindrome m <= n such that every base-10 digit of m is <= the corresponding digit of n. 2

%I #16 Jun 24 2022 14:07:03

%S 0,1,2,3,4,5,6,7,8,9,0,11,11,11,11,11,11,11,11,11,0,11,22,22,22,22,22,

%T 22,22,22,0,11,22,33,33,33,33,33,33,33,0,11,22,33,44,44,44,44,44,44,0,

%U 11,22,33,44,55,55,55,55,55,0,11,22,33,44,55,66,66,66,66,0,11,22,33,44,55,66,77,77,77,0,11,22,33

%N a(n) = largest base-10 palindrome m <= n such that every base-10 digit of m is <= the corresponding digit of n.

%H Reinhard Zumkeller, <a href="/A265525/b265525.txt">Table of n, a(n) for n = 0..9999</a>

%p ispal := proc(n) # test for base-b palindrome

%p local L, Ln, i;

%p global b;

%p L := convert(n, base, b);

%p Ln := nops(L);

%p for i to floor(1/2*Ln) do

%p if L[i] <> L[Ln + 1 - i] then return false end if

%p end do;

%p return true

%p end proc

%p # find max pal <= n and in base-b shadow of n, write in base 10

%p under10:=proc(n) global b;

%p local t1,t2,i,m,sw1,L2;

%p if n mod b = 0 then return(0); fi;

%p t1:=convert(n,base,b);

%p for m from n by -1 to 0 do

%p if ispal(m) then

%p t2:=convert(m,base,b);

%p L2:=nops(t2);

%p sw1:=1;

%p for i from 1 to L2 do

%p if t2[i] > t1[i] then sw1:=-1; break; fi;

%p od:

%p if sw1=1 then return(m); fi;

%p fi;

%p od;

%p end proc;

%p b:=10; [seq(under10(n),n=0..144)]; # Gives A265525

%o (Haskell)

%o a265525 n = a265525_list !! n

%o a265525_list = f a031298_tabf [[]] where

%o f (ds:dss) pss = y : f dss pss' where

%o y = foldr (\d v -> 10 * v + d) 0 ys

%o (ys:_) = dropWhile (\ps -> not $ and $ zipWith (<=) ps ds) pss'

%o pss' = if ds /= reverse ds then pss else ds : pss

%o -- _Reinhard Zumkeller_, Dec 11 2015

%Y Sequences related to palindromic floor and ceiling: A175298, A206913, A206914, A261423, A262038, and the large block of consecutive sequences beginning at A265509.

%Y Cf. A002113, A031298, A265558.

%K nonn,base,look

%O 0,3

%A _N. J. A. Sloane_, Dec 09 2015

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Last modified May 23 18:59 EDT 2024. Contains 372765 sequences. (Running on oeis4.)