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A254789 The number of unlabeled binary trees that contain n distinct subtrees, where a subtree means take any node and everything below that node. 3
1, 1, 3, 15, 111, 1119, 14487, 230943, 4395855, 97608831, 2482988079, 71321533887, 2286179073663, 80984105660415, 3144251526824991, 132867034410319359, 6073991827274809407, 298815244349875677183, 15746949613850439270975, 885279424331353488224511, 52902213099156326247243519 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
a(n) is also the number of compacted binary trees of size n. A compacted binary tree is a directed acyclic graph computed by the UID procedure (see Flajolet et al.) from a given full binary tree. Every edge leading to a subtree that has already been seen during the traversal is replaced by a new kind of edge, a pointer, to the already existing subtree. The size of the compacted binary tree is defined by the number of its internal nodes. See Genitrini et al. - Michael Wallner, Apr 21 2017
LINKS
Alois P. Heinz, Table of n, a(n) for n = 0..371 (terms n = 1..100 from Andrew Szymczak)
Manosij Ghosh Dastidar and Michael Wallner, Asymptotics of relaxed k-ary trees, arXiv:2404.08415 [math.CO], 2024. See p. 1.5.
Philippe Flajolet, Paolo Sipala, and Jean-Marc Steyaert, Analytic variations on the common subexpression problem, in Automata, Languages and Programming (Coventry, 1990), volume 443 of Lecture Notes in Comput. Sci., pages 220-234. Springer, New York, 1990.
Antoine Genitrini, Bernhard Gittenberger, Manuel Kauers and Michael Wallner, Asymptotic Enumeration of Compacted Binary Trees, arXiv:1703.10031 [math.CO], 2017.
Project Euler.chat, Counting Subtrees, (2015).
Marko Riedel, Eric Noeth et al., Distinct subtrees in binary trees, Math StackExchange, February 2015.
Michael Wallner, Combinatorics of lattice paths and tree-like structures (Dissertation, Institut für Diskrete Mathematik und Geometrie, Technische Universität Wien), 2016.
Christoph Wernhard and Wolfgang Bibel, Learning from Łukasiewicz and Meredith: Investigations into Proof Structures (Extended Version), arXiv:2104.13645 [cs.AI], 2021.
FORMULA
a(n) := b(n,0) where b(0,p) := p+1, b(1,p) := p^2+p+1 and b(n+1,p) = sum(b(i,p)*b(n-i,p+i), i=0..n) for n>=2, see Genitrini et al. - Michael Wallner, Apr 21 2017
a(n) = c(n,n) where c(n,m)=(m+1)*c(n-1,m)+c(n,m-1)-(m-1)*c(n-2,m-1) for n>=m>=1, c(n,m)=0 for n<m, and c(n,0)=1 for n>=0. - Michael Wallner, Jan 31 2022
a(n) = Theta(n! 4^n exp(3*a1*n^(1/3)) n^(3/4)) for large n, where a1 = -2.338... = A096714 is the largest root of the Airy function Ai(x) of the first kind; see [Elvey Price, Fang, Wallner 2021]. - Michael Wallner, Jan 31 2022
EXAMPLE
Consider n = 2. For two different subtrees there are (i) the left path on two nodes, (ii) the right path on two nodes, and (iii) the complete tree on three nodes, giving three trees total.
a(3) = 15, as follows:
** First type:
4 paths on 3 nodes:
o
/
o
/
o
** Second type:
complete tree on three nodes with a singleton attached, 4 trees on 4 nodes:
o
/ \
o o
/
o
** Third type:
complete tree on three nodes attached to a singleton at the root, 2 trees on 4 nodes
o
/
o
/ \
o o
** Fourth type:
complete tree on three nodes with two singletons attached in parallel, 2 trees on 5 nodes
o
/ \
o o
/ /
o o
** Fifth type:
complete tree on three nodes with two singletons attached to the same terminal, 2 trees on 5 nodes
o
/ \
o o
/ \
o o
** Sixth type:
complete tree on seven nodes
o
/ \
o o
/ \ |\
o o o o
Total is 4+4+2+2+2+1 = 15.
MATHEMATICA
b[n_ /; n >= 2, p_] := b[n, p] = Sum[b[i, p] b[n-i-1, p+i], {i, 0, n-1}];
b[0, p_] := p + 1;
b[1, p_] := p^2 + p + 1;
a[n_] := b[n, 0];
Table[a[n], {n, 0, 20}] (* Jean-François Alcover, Jul 29 2018 *)
CROSSREFS
Cf. A082161.
Sequence in context: A360864 A201339 A370877 * A112936 A001063 A130168
KEYWORD
nonn,changed
AUTHOR
Marko Riedel, Feb 07 2015
EXTENSIONS
a(9)-a(15) computed by Johannes Waldmann
a(16)-a(20) computed by Andrew Szymczak, added by Eric Noeth, Mar 04 2015
STATUS
approved

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Last modified April 29 12:16 EDT 2024. Contains 372114 sequences. (Running on oeis4.)