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A250404
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Numbers k such that the set of all distinct values of phi of all divisors of k equals the set of all proper divisors of k+1 where phi is the Euler totient function (A000010).
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1
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OFFSET
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1,2
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COMMENTS
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Numbers k such that {phi(d) : d|k} = {d : d|(k+1), d<(k+1)} as sets.
Conjecture: last term is 4294967295.
Sequence differs from A203966 because 83623935 is not in this sequence.
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LINKS
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EXAMPLE
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2 is a term since {phi(d) : d|2} = {1} = {d; d|2, d<2}.
15 is a term since {phi(d) : d|15} = {1, 2, 4, 8} = {d : d|16, d<16}.
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PROG
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(Magma) [n: n in [1..100000] | Set([EulerPhi(d): d in Divisors(n)]) eq Set([d: d in Divisors(n+1) | d lt n+1 ])]
(PARI) isok(n) = {sphi = []; fordiv(n, d, sphi = Set(concat(sphi, eulerphi(d)))); sphi == setminus(Set(divisors(n+1)), Set(n+1)); } \\ Michel Marcus, Nov 23 2014
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CROSSREFS
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KEYWORD
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nonn,more,hard,changed
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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