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A248987
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T(n,k)=Number of length n+4 0..k arrays with every five consecutive terms having two times the sum of some three elements equal to three times the sum of the remaining two
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11
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2, 53, 2, 204, 53, 2, 585, 204, 53, 2, 1326, 585, 204, 53, 2, 2817, 1654, 585, 204, 53, 2, 5028, 4137, 2042, 585, 204, 53, 2, 8789, 7964, 6065, 2494, 585, 204, 53, 2, 13970, 14661, 12644, 8873, 3014, 585, 204, 53, 2, 21601, 23778, 24583, 20128, 12937, 3606
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OFFSET
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1,1
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COMMENTS
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Table starts
.2.53.204.585.1326...2817...5028....8789...13970...21601....31512....45353
.2.53.204.585.1654...4137...7964...14661...23778...39441....60264....90193
.2.53.204.585.2042...6065..12644...24583...40878...72399...115668...180421
.2.53.204.585.2494...8873..20128...41419...70770..133223...222176...361717
.2.53.204.585.3014..12937..32094...70037..123076..245471...426828...726053
.2.53.204.585.3606..18737..51166..118685..214530..452471...819664..1457951
.2.53.204.585.4742..30017..86800..206989..376806..854053..1617708..2998849
.2.53.204.585.6130..47953.147582..362631..665532.1612155..3189728..6170069
.2.53.204.585.7782..76161.250880..637211.1180180.3039269..6274962.12677003
.2.53.204.585.9710.119849.425828.1122703.2100020.5721757.12312020.25999019
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LINKS
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FORMULA
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Empirical for column k:
k=1: a(n) = a(n-1)
k=2: a(n) = a(n-1)
k=3: a(n) = a(n-1)
k=4: a(n) = a(n-1)
k=5: [linear recurrence of order 21]
k=6: [order 51]
Empirical for row n:
n=1: [linear recurrence of order 12; also a polynomial of degree 4 plus a quadratic quasipolynomial with period 6]
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EXAMPLE
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Some solutions for n=6 k=4
..2....2....2....1....2....2....1....3....2....2....3....3....1....2....4....4
..0....4....4....1....0....1....1....2....3....0....2....2....4....2....0....4
..0....2....4....3....4....1....2....4....1....4....1....3....3....3....4....2
..1....0....3....4....4....4....3....1....4....3....2....0....4....1....2....1
..2....2....2....1....0....2....3....0....0....1....2....2....3....2....0....4
..2....2....2....1....2....2....1....3....2....2....3....3....1....2....4....4
..0....4....4....1....0....1....1....2....3....0....2....2....4....2....0....4
..0....2....4....3....4....1....2....4....1....4....1....3....3....3....4....2
..1....0....3....4....4....4....3....1....4....3....2....0....4....1....2....1
..2....2....2....1....0....2....3....0....0....1....2....2....3....2....0....4
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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