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A239478
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Integer solutions of the arithmetic differential equation m' = m + sqrt(m).
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1
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OFFSET
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1,1
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COMMENTS
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m = k^2, where k satisfies k' = (k+1)/2. - Charlie Neder, Mar 08 2019
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LINKS
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EXAMPLE
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For m = 225 we have that m' = 240, sqrt(225) = 15 and 240 = 225 + 15.
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MAPLE
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with(numtheory); P:= proc(q) local n, p, x;
for n from 1 to q do x:=n^2;
if x*add(op(2, p)/op(1, p), p=ifactors(x)[2])=n^2+n then print(n^2);
fi; od; end: P(10^9);
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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STATUS
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approved
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