A236363 Sum of digits of A114440(n).

1, 2, 3, 4, 5, 6, 7, 8, 9, 3, 9, 3, 6, 9, 9, 6, 9, 12, 9, 9, 9, 9, 12, 9, 9, 9, 9, 9, 18, 9, 9, 18, 18, 18, 18, 18, 18, 18, 18, 18, 9, 18, 18, 18, 18, 27, 18, 9, 18, 18, 27, 18, 18, 27, 27, 27, 18, 36, 27, 27, 27, 18, 27, 27, 27, 27, 27, 27, 27, 27, 27, 36, 36, 36, 36, 27

Offset

1,2

Comments

Because A114440 is finite, this sequence is necessarily also finite.

Note that after a(23), all terms are divisible by 9 since all the terms that take three steps to arrive at 1 are multiples of 9 so the sum of digits of their predecessors must also be a multiple of 9.

Links

Ray Chandler, Table of n, a(n) for n = 1..15095

Formula

a(n) = A007953(A114440(n)).

Crossrefs

Cf. A005349, A007953, A114440, A235600.

Sequence in context: A245346 A028898 A081502 * A278061 A079828 A061229

Adjacent sequences: A236360 A236361 A236362 * A236364 A236365 A236366

Keyword

nonn,base,fini,full

Author

Ray Chandler, Jan 23 2014

Status

approved