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A235063
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Continued fraction expansion of Sum(i=1..inf, 1/2^(2^i+1) ).
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0
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2, 2, 4, 2, 8, 3, 8, 1, 8, 3, 4, 2, 12, 2, 8, 1, 8, 3, 4, 2, 8, 3, 8, 1, 12, 2, 4, 2, 12, 2, 8, 1, 8, 3, 4, 2, 8, 3, 8, 1, 8, 3, 4, 2, 12, 2, 8, 1, 12, 2, 4, 2, 8, 3, 8, 1, 12, 2, 4, 2, 12, 2, 8, 1, 8, 3, 4, 2, 8, 3, 8, 1, 8, 3, 4, 2, 12, 2, 8, 1, 8, 3, 4, 2, 8, 3, 8, 1, 12, 2, 4, 2, 12, 2, 8, 1, 12, 2, 4
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OFFSET
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0,1
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LINKS
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FORMULA
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0.40821075451094657... = (1/2) A007400.
Recurrence: a(8n)=1, a(8n+4)=a(16n+14)=a(32n+26)=2, a(16n+6)=a(32n+10)=3, a(8n+3)=4, a(8n+7)=a(16n+5)=a(32n+9)=8, a(16n+13)=a(32n+25)=12, a(8n+1)=a(4n+1), a(8n+2)=a(4n+2), starting 2,2,4 (conjectured).
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EXAMPLE
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0.40821075451094657... = 2/(2+1/(2+1/(4+1/(2+1/(8+1/(3+1/8...
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PROG
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(PARI) a(n)=contfrac(suminf(i=0, 1/2^(2^i+1)))[n+1]
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CROSSREFS
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KEYWORD
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cofr,nonn
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AUTHOR
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STATUS
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approved
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