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A231276
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Integer areas of the inner vecten triangles of integer-sided triangles.
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1
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5, 20, 21, 23, 29, 39, 41, 45, 59, 63, 80, 83, 84, 92, 116, 125, 131, 156, 164, 173, 180, 189, 203, 207, 227, 236, 237, 245, 252, 257, 261, 269, 320, 329, 332, 336, 351, 368, 369, 371, 405, 464, 479, 497, 500, 524, 525, 531, 567, 575, 605, 623, 624, 656, 663
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OFFSET
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1,1
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COMMENTS
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Consider the internal erection of three squares on the sides of a triangle ABC. These centers form a triangle IJK. The area of the inner vecten triangle is
A' = A - (a^2 + b^2 + c^2)/8,
where A is the area of the reference triangle. Its side lengths are
a' = sqrt((b^2 + c^2 - 4*A)/2),
b' = sqrt((a^2 + c^2 - 4*A)/2),
c' = sqrt((a^2 + b^2 - 4*A)/2).
The circumcircle of the inner vecten circle is the inner vecten circle.
Properties of this sequence:
The primitive triangles are 5, 21, 23, 29, 39, 41, ...
The nonprimitive triangles of areas 4*a(n), 9*a(n), ..., p^2*a(n), ... are in the sequence.
It appears that if the triangles are isosceles, one of the sides of the inner vecten triangles is integer (see the table below).
The following table gives the first values (A, A', a, b, c, a', b', c') where A is the area of the initial triangles, A' is the area of the inner vecten triangles, a, b, c are the integer sides of the initial triangles, and a', b', c' are the sides of the inner vecten triangles.
-----------------------------------------------------------------------
| A' | A | a | b | c | a' | b' | c'
-----------------------------------------------------------------------
| 5 | 48 | 10 | 10 | 12 | sqrt(26) | sqrt(26) | 2
| 20 | 192 | 20 | 20 | 24 | 2*sqrt(26) | 2*sqrt(26) | 4
| 21 | 240 | 20 | 20 | 26 | 14 | sqrt(58) | sqrt(58)
| 23 | 1680 | 48 | 74 | 74 | 46 | sqrt(530) | sqrt(530)
| 29 | 1680 | 50 | 68 | 78 | sqrt(1994)| 2*sqrt(233)| sqrt(202)
| 39 | 1680 | 58 | 58 | 80 | sqrt(1522)| sqrt(1522)| 2
| 41 | 336 | 26 | 28 | 30 | sqrt(170) | 2*sqrt(29) | sqrt(58)
| 45 | 432 | 30 | 30 | 36 | 3*sqrt(26) | 3*sqrt(26) | 6
| 59 | 1440 | 50 | 58 | 72 | sqrt(1394)| sqrt(962)| 2*sqrt(13)
| 63 | 480 | 32 | 34 | 34 | 14 | sqrt(130)| sqrt(130)
| 80 | 768 | 40 | 40 | 48 | 4*sqrt(26) | 4*sqrt(26) | 8
| 83 | 2880 | 74 | 78 | 104 | sqrt(2690)| sqrt(2386)| 2*sqrt(5)
.............................................................
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REFERENCES
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H. S. M. Coxeter and S. L. Greitzer, Points and Lines Connected with a Triangle, Ch. 1 in Geometry Revisited, Washington DC, Math. Assoc. Amer., pp. 1-26 and 96-97, 1967.
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LINKS
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EXAMPLE
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5 is in the sequence. We use two ways:
First way: with the triangle (10, 10, 12) the formula A' = A - (a^2 + b^2 + c^2)/8 gives directly the result: A' = 48 - (10^2 + 10^2 + 12^2)/8 = 5 where the area A = 48 is obtained by Heron's formula A = sqrt(s*(s-a)*(s-b)*(s-c)) = sqrt(16*(16-10)*(16-10)*(16-12)) = 48, where s is the semiperimeter.
Second way: by calculation of the sides a', b', c' and by use of Heron's formula.
a’ = sqrt((b^2 + c^2 - 4*A)/2) = sqrt((10^2 + 12^2 - 4*48)/2) = sqrt(26);
b’ = sqrt((a^2 + c^2 - 4*A)/2) = sqrt((10^2 + 12^2 - 4*48)/2) = sqrt(26);
c’ = sqrt((a^2 + b^2 - 4*A)/2) = sqrt((10^2 + 10^2 - 4*48)/2) = 2.
Now we use Heron's formula with (a',b',c'). We find A' = sqrt(s1*(s1-a')*(s1-b')*(s1-c')) with:
s1 = (a' + b' + c')/2 = (sqrt(26) + sqrt(26) + 2)/2.
We find A' = 5.
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MATHEMATICA
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nn = 500; lst = {}; Do[s = (a + b + c)/2; If[IntegerQ[s], area2 = s (s - a) (s - b) (s - c); t = (a^2 + b^2 + c^2)/8; If[0 < area2 && Sqrt[area2] - t > 0 && IntegerQ[Sqrt[area2] - t], AppendTo[lst, Sqrt[area2] - t]]], {a, nn}, {b, a}, {c, b}]; Union[lst]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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