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A228845
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Least m such that (2k+1)*2^m + 1 is a prime factor of the Fermat number 2^(2^n) + 1.
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2
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1, 2, 4, 8, 16, 7, 8, 9, 11, 11, 12, 13, 14
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OFFSET
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0,2
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COMMENTS
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a(n) >= n + 2 for n >= 2.
a(n) = A228846(n) if 2^(2^n) + 1 is prime or semiprime.
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LINKS
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CROSSREFS
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KEYWORD
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nonn,hard,more
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AUTHOR
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STATUS
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approved
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