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A224837
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Surface area of Johnson square pyramid (rounded down) with all the edge-lengths equal to n.
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2
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2, 10, 24, 43, 68, 98, 133, 174, 221, 273, 330, 393, 461, 535, 614, 699, 789, 885, 986, 1092, 1204, 1322, 1445, 1573, 1707, 1846, 1991, 2141, 2297, 2458, 2625, 2797, 2975, 3158, 3346, 3540, 3740, 3945, 4155, 4371, 4592, 4819, 5051, 5289, 5532, 5781, 6035, 6294
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OFFSET
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1,1
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COMMENTS
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Johnson square pyramid: a square base with four equilateral triangular-faces. All the edge-lengths are equal.
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LINKS
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FORMULA
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a(n) = floor((1+sqrt(3))*n^2).
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EXAMPLE
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a(3)=24: Surface area = (1+sqrt(3))*k^2 = (1+sqrt(3))*3^2 = 24.58845727 and floor(24.58845727) = 24.
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MAPLE
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KD:= proc() local a, b; a:=evalf(1+sqrt(3))*k^2; b:=floor(a); RETURN(b): end: seq(KD(), k=1..100);
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MATHEMATICA
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Table[Floor[(1+Sqrt[3])*k^2], {k, 500}]
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PROG
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(PARI) vector(500, k, floor((1+sqrt(3))*k^2))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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