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COMMENTS
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From Balmer series.
a(n) and differences a(n+1) - a(n):
-1, 0, 0, 1, -3, 4, 2, 9, 3, 16, 6, 25, ...
1, 0, 1, -4, 7, -2, 7, -6, 13, -10, 19, -20, ... = b(n).
b(2*n) = 1, 1, 7, 7, 13, 19, 31, 37, 49, 61, 79, ... = c(n) + 1.
c(n) = 0, 0, 6, 6, 12, 18, 30, 36, 48, 60, 78, ... = A005563(n-1) - A214297(n) = 6*A001971(n).
a(n+3) - a(n) = 2, -3, 4, 1, 12, -1, 14, -3, 22, -11, 30, -13, 44, ... = e(n).
e(2*n+1) = -3, 1, -1, -3, -11, -13, -21, -29, -43, -51, -65, -79, ... of signature (2,-1,0,1,-2,1).
Differ. = 4, -2, -2, -8, -2, -8, -8, -14, -8, -14, -14, -20, -14, ... . The different numbers appear four times.
Differ. = -6, 0, -6, 6, -6, 0, -6, 6, -6, 0, -6, 6, -6, ... . Of period 4. Like c(n+2) - 2*c(n+1) - c(n).
Note that a(2*n) + a(2*n+1) = -1, 1, 1, 11, 19, 31, 41, 61, ... increases after the last 1 despite 6 is before 5.
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