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A213080
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Decimal expansion of Product_{n>=1} n! /(sqrt(2*Pi*n) * (n/e)^n * (1+1/n)^(1/12)).
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3
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1, 0, 4, 6, 3, 3, 5, 0, 6, 6, 7, 7, 0, 5, 0, 3, 1, 8, 0, 9, 8, 0, 9, 5, 0, 6, 5, 6, 9, 7, 7, 7, 6, 0, 3, 7, 1, 0, 1, 9, 7, 4, 2, 1, 8, 1, 1, 3, 2, 6, 4, 4, 4, 2, 4, 4, 1, 5, 8, 7, 5, 3, 4, 0, 4, 2, 0, 3, 5, 7, 5, 1, 5, 6, 3, 7, 4, 4, 5, 7, 0, 7, 2, 5, 4, 8, 5, 8
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OFFSET
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1,3
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COMMENTS
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Just as Stirling's formula for the asymptotic expansion of n! involves the constant sqrt{2 Pi}, the asymptotic expansion of the product of all binomial coefficients in a row of Pascal's triangle involves a constant, the reciprocal of the constant C defined and evaluated here.
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LINKS
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FORMULA
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Let A denote the Glaisher-Kinkelin constant. Then
C = (exp(1)^(1/12)*(2*Pi)^(1/4))/A^2 = exp(2*zeta'(-1)-1/12)*(2*Pi)^(1/4).
A closely related constant is K = Product_{n>=1} (n!*(e/n)^(n+1/2))/ ((1+1/(n+1/2))^(1/12)*sqrt(2*Pi*e)) = (2^(1/6)*(3*e)^(1/12)*Pi^(1/4))/A^2 = exp(2*zeta'(-1)-1/12)*2^(1/6)*3^(1/12)*Pi^(1/4) = 1.082293504658977773529439... - Peter Luschny, Jun 22 2012
sqrt(C) = Limit_{n>=1} (Product_{k=1..n-1} k!) / f(n) where f(n) = (2*Pi)^(n/2-1/8)*exp(1/24-3/4*n^2)*n^(1/2*n^2-1/12). - Peter Luschny, Jun 23 2012
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EXAMPLE
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1.0463350667705031...
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MAPLE
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exp(2*Zeta(1, -1)-1/12)*(2*Pi)^(1/4); evalf(%, 100); # Peter Luschny, Jun 22 2012
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MATHEMATICA
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RealDigits[(Exp[1]^(1/12) (2 Pi)^(1/4))/Glaisher^2, 10, 100][[1]] (*Peter Luschny, Jun 22 2012 *)
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PROG
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(Sage)
import mpmath
mpmath.mp.pretty=True; mpmath.mp.dps = 200 #precision
mpmath.exp(2*mpmath.zeta(-1, 1, 1)-1/12)*(2*pi)^(1/4) # Peter Luschny, Jun 22 2012
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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