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A210996 Number of free polyominoes with 2n cells. 9
1, 1, 5, 35, 369, 4655, 63600, 901971, 13079255, 192622052, 2870671950, 43191857688, 654999700403, 9999088822075, 153511100594603, 2368347037571252, 36695016991712879, 570694242129491412, 8905339105809603405, 139377733711832678648, 2187263896664830239467, 34408176607279501779592 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
It appears that we can write A216492(n) < A216583(n) < A056785(n) < A056786(n) < a(n) < A210988(n) < A210986(n), if n >= 3. - Omar E. Pol, Sep 16 2012
LINKS
Herman Tulleken, Polyominoes 2.2: How they fit together, (2019).
Eric Weisstein's World of Mathematics, Polyomino
Wikipedia, All 5 free tetrominoes, Illustration of a(2) = 5.
Wikipedia, All 35 free hexominoes, Illustration of a(3) = 35.
Wikipedia, All 369 free octominoes, Illustration of a(4) = 369.
Wikipedia, Polyomino
FORMULA
a(n) = A000105(2n).
a(n) = A213376(n) + A056785(n). - R. J. Mathar, Feb 08 2023
EXAMPLE
For n = 1 there is only one free domino. For n = 2 there are 5 free tetrominoes. For n = 3 there are 35 free hexominoes. For n = 4 there are 369 free octominoes (see link section).
MATHEMATICA
A000105 = Cases[Import["https://oeis.org/A000105/b000105.txt", "Table"], {_, _}][[All, 2]];
Partition[A000105, 2][[All, 1]] (* Jean-François Alcover, Jan 03 2020 *)
CROSSREFS
Bisection of A000105.
Sequence in context: A258902 A371028 A125864 * A204290 A059865 A247596
KEYWORD
nonn
AUTHOR
Omar E. Pol, Sep 15 2012
EXTENSIONS
More terms from John Mason, Apr 15 2023
STATUS
approved

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Last modified April 30 18:46 EDT 2024. Contains 372141 sequences. (Running on oeis4.)