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A198383
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a(n) = Sum_{k=1..n} 2^(n mod k).
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1
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1, 2, 4, 5, 10, 10, 20, 22, 37, 40, 80, 72, 144, 158, 278, 283, 566, 548, 1096, 1120, 2106, 2162, 4324, 4210, 8389, 8584, 16650, 16772, 33544, 33194, 66388, 66968, 131882, 132690, 265222, 263607, 527214, 530138, 1052078, 1054254, 2108508, 2103282, 4206564, 4216760
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OFFSET
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1,2
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COMMENTS
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A more precise asymptotic formula is given in the link.
If n is prime then a(n)=2*a(n-1).
It appears that for every (deficient, abundant)-pair of numbers (11+6x, 11+6x+1), a(11+6x) > a(11+6x+1).
(End)
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LINKS
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FORMULA
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a(n) = 2^ceiling(n/2) + O(2^(n/3)).
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MATHEMATICA
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PROG
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(PARI) a(n) = sum(k=1, n, 2^(n%k))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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