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%I #5 Mar 30 2012 18:57:39
%S 1,4,2,13,8,3,45,32,19,8,120,92,64,38,15,300,242,184,128,75,30,692,
%T 578,464,352,243,142,56,1524,1306,1088,872,659,454,264,104,3225,2818,
%U 2411,2006,1604,1210,831,482,189,6625,5878,5131,4386,3644,2910,2191
%N Mirror of the triangle A193949.
%C A193950 is obtained by reversing the rows of the triangle A193949.
%F Write w(n,k) for the triangle at A193949. The triangle at A193950 is then given by w(n,n-k).
%e First six rows:
%e 1
%e 4.....2
%e 13....8.....3
%e 45....32....19....8
%e 120...92....64....38....15
%e 300...242...184...128...75...30
%t z = 12;
%t p[n_, x_] := Sum[Fibonacci[k + 1]*x^(n - k), {k, 0, n}];
%t q[n_, x_] := Sum[(k + 1) (n + 1)*x^(n - k), {k, 0, n}];
%t t[n_, k_] := Coefficient[p[n, x], x^k]; t[n_, 0] := p[n, x] /. x -> 0;
%t w[n_, x_] := Sum[t[n, k]*q[n + 1 - k, x], {k, 0, n}]; w[-1, x_] := 1
%t g[n_] := CoefficientList[w[n, x], {x}]
%t TableForm[Table[Reverse[g[n]], {n, -1, z}]]
%t Flatten[Table[Reverse[g[n]], {n, -1, z}]] (* A193949 *)
%t TableForm[Table[g[n], {n, -1, z}]]
%t Flatten[Table[g[n], {n, -1, z}]] (* A193950 *)
%Y Cf. A193949.
%K nonn,tabl
%O 0,2
%A _Clark Kimberling_, Aug 10 2011
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