|
|
A189322
|
|
Number of nondecreasing arrangements of n+2 numbers in 0..5 with the last equal to 5 and each after the second equal to the sum of one or two of the preceding four.
|
|
1
|
|
|
8, 12, 21, 33, 54, 84, 119, 157, 195, 233, 271, 309, 347, 385, 423, 461, 499, 537, 575, 613, 651, 689, 727, 765, 803, 841, 879, 917, 955, 993, 1031, 1069, 1107, 1145, 1183, 1221, 1259, 1297, 1335, 1373, 1411, 1449, 1487, 1525, 1563, 1601, 1639, 1677, 1715
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
|
|
LINKS
|
|
|
FORMULA
|
Empirical: a(n) = 38*n - 147 for n>6.
Empirical g.f.: x*(8 - 4*x + 5*x^2 + 3*x^3 + 9*x^4 + 9*x^5 + 5*x^6 + 3*x^7) / (1 - x)^2. - Colin Barker, May 02 2018
|
|
EXAMPLE
|
Some solutions for n=3:
..1....1....2....5....1....1....1....1....1....4....1....2....3....2....1....0
..2....2....3....5....3....2....2....1....3....5....3....5....5....3....4....5
..2....3....3....5....3....2....3....2....4....5....4....5....5....3....4....5
..4....3....5....5....4....3....4....3....5....5....4....5....5....3....4....5
..5....5....5....5....5....5....5....5....5....5....5....5....5....5....5....5
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|