%I #9 Sep 08 2022 08:45:56
%S 0,1,1,0,0,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,1,0,0,1,1,0,1,1,0,0,1,1,
%T 0,1,1,0,0,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,1,0,0,1,1,
%U 0,1,1,0,0,1,1,0,1,1,0,0,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,1,0,0,1,1,0,1,1
%N a(n) = [n*r] - [k*r] - [n*r-k*r], where r=1/sqrt(2), k=5, [ ]=floor.
%C See A188014.
%H G. C. Greubel, <a href="/A188321/b188321.txt">Table of n, a(n) for n = 1..10000</a>
%F a(n) = [n*r]-[5*r]-[n*r-5*r], where r=1/sqrt(2).
%t r=2^(-1/2); k=5;
%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (*A188321*)
%t Flatten[Position[t,0]] (*A188322*)
%t Flatten[Position[t,1]] (*A188323*)
%o (PARI) for(n=1, 100, print1(floor(n/sqrt(2)) - floor(5/sqrt(2)) - floor((n-5)/sqrt(2)), ", )) \\ _G. C. Greubel_, Apr 11 2018
%o (Magma) [Floor(n/Sqrt(2)) - Floor(5/Sqrt(2)) - Floor((n-5)/Sqrt(2)): n in [1..100]]; // _G. C. Greubel_, Apr 11 2018
%Y Cf. A188014, A188322, A188323.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 28 2011
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