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A186642 Decimal expansion of the "squircle" perimeter. 0
7, 0, 1, 7, 6, 9, 7, 9, 4, 3, 5, 6, 4, 0, 4, 1, 6, 4, 7, 1, 0, 6, 4, 9, 4, 1, 6, 3, 9, 3, 1, 8, 1, 1, 6, 9, 3, 9, 8, 0, 0, 8, 7, 5, 0, 4, 9, 7, 2, 4, 4, 9, 3, 4, 3, 2, 2, 8, 8, 6, 1, 0, 3, 5, 6, 0, 7, 3, 9, 2, 2, 1, 1, 6, 1, 8, 1, 8, 8, 8, 3, 5, 1, 3, 2, 3, 8, 8, 3, 9, 3, 0, 0, 5, 0, 3, 4, 0, 7, 1 (list; constant; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
This squircle constant can also be computed as a series in terms of incomplete beta function with coefficients from sequences A002596 and A120777:
a(n) = (-1)^(n+1) numerator((2n-3)!!/n!) ( sequence A002596);
b(n) = denominator(binomial(2n+2, n+1)/2^(2n+1)) ( sequence A120777).
Generic term:
u(n) = (a(n)/b(n-1))*beta(1/2, (6n+1)/4, 1-(3/2)*n).
Here is the series computed up to 5 terms:
4*2^(3/4) + sum(u(n), {n, 1, 5}) =
4*2^(3/4) + beta(1/2, 7/4, -1/2) - (1/4)*beta(1/2, 13/4, -2) + (1/8)* beta(1/2, 19/4, -7/2) - (5/64)*beta(1/2, 25/4, -5) + (7/128)*beta(1/2, 31/4, -13/2).
It evaluates to 7.018901897260651...
Numeric check with 10000 terms:
4*2^(3/4) + sum(u(n), {n, 1, 10000}) = 7.017697943556135...
LINKS
Eric Weisstein's World of Mathematics, Squircle
FORMULA
-((3^(1/4) MeijerG[{{1/3, 2/3, 5/6, 1, 4/3}, {}}, {{1/12, 5/12, 7/12, 3/4, 13/12}, {}}, 1])/(16 Sqrt[2] Pi^(7/2) Gamma[5/4])). - Eric W. Weisstein, Oct 25 2011
EXAMPLE
7.01769794356404...
MATHEMATICA
First @ RealDigits[N[2*Integrate[Sqrt[1 + x^(3/2)/(1 - x)^(3/2)]/x^(3/4), {x, 0, 1/2}], 100]]
(* This other series formula gives 100 correct digits: *)
First @ RealDigits[1/Sqrt[Pi]*NSum[(-1)^(n+1)*Gamma[n - 1/2]*Beta[1/2, (6n + 1)/4, 1 - (3/2)n] / n!, {n, 0, Infinity}, WorkingPrecision -> 100, Method -> "AlternatingSigns"], 10, 100]
CROSSREFS
Cf. A175576 (unit squircle area).
Sequence in context: A202354 A324498 A243908 * A153626 A297787 A101031
KEYWORD
cons,easy,nonn
AUTHOR
STATUS
approved

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Last modified May 17 08:10 EDT 2024. Contains 372579 sequences. (Running on oeis4.)