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A184726 a(n) = A005408(n-1)/A090368(n-1) for n > 2 and a(n) = 0 for n <= 2. 1

%I #6 Mar 30 2012 17:25:56

%S 0,0,1,1,1,3,1,1,5,1,1,7,1,5,9,1,1,11,7,1,13,1,1,15,1,7,17,1,11,19,1,

%T 1,21,13,1,23,1,1,25,11,1,27,1,17,29,1,13,31,19,1,33,1,1,35,1,1,37,1,

%U 23,39,17,11,41,25,1,43,1,19,45,1,1,47

%N a(n) = A005408(n-1)/A090368(n-1) for n > 2 and a(n) = 0 for n <= 2.

%C a(n) is the "level" of odd numbers.

%C The decomposition of odd numbers into weight * level + gap is A005408(n) = A090368(n-1) * a(n) + 2 if a(n) > 0.

%H Rémi Eismann, <a href="/A184726/b184726.txt">Table of n, a(n) for n = 1..10000</a>

%e For n = 3 we have A005408(2)/A090368(2)= 3 / 3 = 1; hence a(3) = 1.

%e For n = 24 we have A005408(23)/A090368(23)= 45 / 3 = 14; hence a(24) = 15.

%Y Cf. A005408, A090368, A117078, A117563, A001223.

%K nonn

%O 1,6

%A _Rémi Eismann_, Jan 20 2011

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