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A184587 a(n) = floor((n+1/2)*s), where s=(5+sqrt(5))/4; complement of A184586. 3

%I #8 Sep 08 2017 09:53:35

%S 2,4,6,8,9,11,13,15,17,18,20,22,24,26,28,29,31,33,35,37,38,40,42,44,

%T 46,47,49,51,53,55,56,58,60,62,64,66,67,69,71,73,75,76,78,80,82,84,85,

%U 87,89,91,93,94,96,98,100,102,104,105,107,109,111,113,114,116,118,120,122,123,125,127,129,131,132,134,136,138,140,142,143,145,147,149,151,152,154,156,158,160,161,163,165,167,169,170,172,174,176,178,179,181,183,185,187,189,190,192,194,196,198,199,201,203,205,207,208,210,212,214,216,217

%N a(n) = floor((n+1/2)*s), where s=(5+sqrt(5))/4; complement of A184586.

%F a(n)=floor[(n+1/2)s], where s=(5+sqrt(5))/4.

%t r=5^(1/2); c=1/2; s=r/(r-1);

%t Table[Floor[n*r-c*r],{n,1,120}] (* A184586 *)

%t Table[Floor[n*s+c*s],{n,1,120}] (* A184587 *)

%Y Cf. A184586.

%K nonn

%O 1,1

%A _Clark Kimberling_, Jan 17 2011

%E Name and formula corrected by _Michel Dekking_, Sep 08 2017

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