(PARI) {a(n)=(n+1)^(n-1)*(2*n)!/n!}
(PARI) N=50; /* up to order N */
A(x)=sum(n=0, N-1, if (n%2==1, 0, (n/2+1)^(n/2-1)/(n/2)!*x^n) )+O(x^N); /* e.g.f. */
v=Vec(serlaplace(A(x))) /* gives sequence as vector with interpolated zeros */
/* Now check that e.g.f. satisfies functional equation: */
A(x)-exp(x^2*A(x)) /* ==O(x^50) "==zero" */
(PARI)
N = 28; x = 'x + O('x^N); y = 'y; Fxy = exp(x^2*y) - y;
seq() = {
my(y0 = 1 + O('x^N), y1=0);
for (k = 1, N,
y1 = y0 - subst(Fxy, y, y0)/subst(deriv(Fxy, y), y, y0);
if (y1 == y0, break()); y0 = y1);
Vec(y0);
};
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