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A174734
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Prime numbers n such that 2n-1 and 3n-2 are prime.
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5
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3, 7, 37, 211, 271, 307, 331, 337, 601, 727, 1171, 1237, 1297, 1531, 1657, 2221, 2281, 2557, 3037, 3061, 3067, 4261, 4447, 4801, 4951, 5227, 5581, 5851, 6151, 6361, 6691, 6841, 6967, 7621, 7681, 7687, 7867, 8017, 8167, 8191, 8287, 8521, 8527, 8647, 8941
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OFFSET
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1,1
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COMMENTS
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If n, 2n-1 and 3n-2 are prime numbers, and if n >= 5, then n*(2*n-1)*(3*n-2) is a Carmichael number (A033502).
Proof: there exist numbers m such that n=6m+1 is prime (if n=6m+5, then 2n-1 = 12m+9 is composite). Let p=(6m+1)(12m+1)(18m+1) = a*b*c. Then p-1 = 6*12*18*m^3 + (6*12 + 6*18 + 12*18)*m^2 + (6 + 12 + 19)*m, so p-1 is divisible by a-1=6m, by b-1=12m, and by c-1=18m; thus p is a Carmichael number.
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REFERENCES
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R. K. Guy, Unsolved Problems in Number Theory, A13.
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LINKS
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EXAMPLE
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For n=3, 2n-1 = 5, 3n-2 = 7.
For n=7, 2n-1 = 13, 3n-2 = 19 and 7*13*19 = 1729 (a Carmichael number).
For n=37, 2n-1 = 73, 3n-2 = 109 and 37*73*109 = 294409 (a Carmichael number).
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MAPLE
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with(numtheory): for n from 2 to 15000 do: if type(n, prime)=true and type(2*n-1, prime)=true and type(3*n-2, prime)=true then print (n):else fi:od:
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MATHEMATICA
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PROG
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(Magma) [ n: n in PrimesUpTo(10000) | IsPrime(2*n-1) and IsPrime(3*n-2) ];
(PARI) forprime(p=3, 10^3, isprime(2*p-1) && isprime(3*p-2) && print1(p, ", ")); \\ Joerg Arndt, Nov 29 2014
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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