|
|
A171407
|
|
This is a sequence demonstrating a congruence property of second order exponential functions. Let f(n) = a^(b^n) + c where a,b,c & n belong to N, a, b & c fixed. Then f(n + k*phi(phi(f(n)) is congruent to 0 (mod(f(n)). Here k belongs to N. This is a sequence of quotients generated by f(n + k*f(n))/f(n) when a & b = 2, c= 3 and n = 1. when a & b = 2 and c =3 when n = 1.
|
|
0
|
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
The name contains an unmatched parenthesis. - Editors, Mar 13 2024
|
|
LINKS
|
|
|
EXAMPLE
|
a(n) = 2^2^n + 3 = 7 when n = 1. phi(phi(7)) = 2. 2^2^(1 + 2*k) + 3 = 259; 259/7 = 37.
|
|
PROG
|
(PARI) a(k)=(2^2^(1 + 2*k) + 3)/7
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,uned,bref
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|