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A164413 Number of binary strings of length n with no substrings equal to 0000, 0001 or 1001. 1

%I #29 Oct 27 2017 17:54:50

%S 1,2,4,8,13,22,36,58,94,152,246,398,644,1042,1686,2728,4414,7142,

%T 11556,18698,30254,48952,79206,128158,207364,335522,542886,878408,

%U 1421294,2299702,3720996,6020698,9741694,15762392,25504086,41266478,66770564,108037042

%N Number of binary strings of length n with no substrings equal to 0000, 0001 or 1001.

%C Essentially the same as A022112. - _R. J. Mathar_, Nov 30 2011

%H David A. Corneth, <a href="/A164413/b164413.txt">Table of n, a(n) for n = 0..1999</a> (terms n = 4..500 from R. H. Hardin)

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (1,1).

%F From _Colin Barker_, Oct 27 2017: (Start)

%F G.f.: -(x^2+1)*(x^2-x+1)*(x+1)^2/(x^2+x-1).

%F a(n) = 2*(((1 - sqrt(5))/2)^n + ((1 + sqrt(5))/2)^n) for n>4.

%F a(n) = a(n-1) + a(n-2) for n>6.

%F (End)

%o (PARI) Vec(-(x^2+1)*(x^2-x+1)*(x+1)^2/(x^2+x-1) + O(x^50)) \\ _Colin Barker_, Oct 27 2017

%o (PARI) first(n) = {my(start = [1, 2, 4, 8, 13, 22, 36]); if(n <= 7, return(vector(n+1, i, start[i]))); res = concat(start, vector(n-7)); for(i=8, n,

%o res[i] = res[i-1] + res[i-2]); res} \\ _David A. Corneth_, Oct 27 2017

%K nonn,easy

%O 0,2

%A _R. H. Hardin_, Aug 14 2009

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