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A156638
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Numbers k such that k^2 + 2 == 0 (mod 9).
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8
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4, 5, 13, 14, 22, 23, 31, 32, 40, 41, 49, 50, 58, 59, 67, 68, 76, 77, 85, 86, 94, 95, 103, 104, 112, 113, 121, 122, 130, 131, 139, 140, 148, 149, 157, 158, 166, 167, 175, 176, 184, 185, 193, 194, 202, 203, 211, 212, 220, 221, 229, 230, 238, 239, 247, 248, 256
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OFFSET
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1,1
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COMMENTS
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Numbers congruent to 4 or 5 mod 9.
Numbers which are not the sum of 3 cubes.
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REFERENCES
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Henri Cohen, Number Theory Volume I: Tools and Diophantine Equations. Springer Verlag (2007) p. 380. - Artur Jasinski, Apr 30 2010
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LINKS
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Andrew Sutherland, Sums of three cubes, Slides of a talk given May 07 2020 on the Number Theory Web.
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FORMULA
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For n > 2, a(n) = a(n-2) + 9.
a(n) = a(n-1) + a(n-2) - a(n-3), n>3.
a(n) = 9*n/2 - 9/4 - 7*(-1)^n/4.
G.f.: x*(4 + x + 4*x^2)/((1 + x)*(1 - x)^2). (End)
E.g.f.: 4 + ((18*x - 9)*exp(x) - 7*exp(-x))/4. - David Lovler, Aug 21 2022
Sum_{n>=1} (-1)^(n+1)/a(n) = tan(Pi/18)*Pi/9. - Amiram Eldar, Sep 26 2022
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MAPLE
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MATHEMATICA
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Select[Range[300], PowerMod[#, 2, 9]==7&] (* Harvey P. Dale, Jan 31 2023 *)
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PROG
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(Magma) [9*n/2 - 9/4 - 7*(-1)^n/4 : n in [1..80]]; // Wesley Ivan Hurt, Aug 16 2015
(PARI) a(n) = (18*n - 9 - 7*(-1)^n)/4 \\ David Lovler, Aug 21 2022
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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