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A153063
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a(n)=floor(b(n)), where b(0)=1, b(n)=b(n-1)^2-n^b(n-1).
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1
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OFFSET
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0,5
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COMMENTS
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The supplied Mathematica and PARI code corresponds to an initial value a(-1)=b(-1)=1 from which a(0)=b(0) is computed to be equal to 1.
The next term is approximately
-1.642155991293887705947531213655414816023738489781202992764677529*10^3948835
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LINKS
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MATHEMATICA
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a=1; lst={}; Do[a=a^2-n^a; AppendTo[lst, Floor[a]], {n, 0, 7}]; lst
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PROG
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(PARI) a=1; for(n=0, 7, print1(floor(a=a^2-n^a)", ")) \\ - R. Gerbicz, Nov 27 2010
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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