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A152998 Toothpick sequence on the semi-infinite square grid. 15
0, 1, 3, 5, 7, 11, 17, 21, 23, 27, 33, 39, 47, 61, 77, 85, 87, 91, 97, 103, 111, 125, 141, 151, 159, 173, 191, 211, 241, 285, 325, 341, 343, 347, 353, 359, 367, 381, 397, 407, 415, 429, 447, 467, 497, 541, 581, 599, 607, 621, 639 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
Contribution from Omar E. Pol, Oct 01 2011 (Start):
On the semi-infinite square grid, at stage 0, we start from a vertical half toothpick at [(0,0),(0,1)]. This half toothpick represents one of the two components of the first toothpick placed in the toothpick structure of A139250. Consider only the toothpicks of length 2, so a(0) = 0.
At stage 1, we place an orthogonal toothpick of length 2 centered at the end, so a(1) = 1.
In each subsequent stage, for every exposed toothpick end, place an orthogonal toothpick centered at that end.
The sequence gives the number of toothpicks after n stages. A152968 (the first differences) gives the number of toothpicks added to the structure at n-th stage.
For more information see A139250. (End)
LINKS
David Applegate, Omar E. Pol and N. J. A. Sloane, The Toothpick Sequence and Other Sequences from Cellular Automata, Congressus Numerantium, Vol. 206 (2010), 157-191. [There is a typo in Theorem 6: (13) should read u(n) = 4.3^(wt(n-1)-1) for n >= 2.]
FORMULA
a(n) = (A139250(n+1)-1)/2.
From Omar E. Pol, Oct 01 2011: (Start)
a(n) = A139250(n+1) - A153003(n) + A153000(n-1) - 1, if n >= 1.
a(n) = A153003(n) - A153000(n-1), if n >= 1.
a(n) = 2*A153000(n-1) + 1, if n >= 1.
(End)
a(n) = (A187220(n+2) - 3)/4. - Omar E. Pol, Feb 18 2013
CROSSREFS
Sequence in context: A349638 A045397 A211409 * A222176 A331891 A331896
KEYWORD
nonn
AUTHOR
Omar E. Pol, Dec 19 2008, Dec 23 2008, Jan 02 2008
STATUS
approved

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Last modified May 2 03:56 EDT 2024. Contains 372178 sequences. (Running on oeis4.)