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A147554
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Primes p such that p^2 divides p.p.p where dot "." means concatenation.
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2
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OFFSET
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1,1
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COMMENTS
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Primes p dividing 10^(2*d)+10^d+1 where d=ceiling(log(p)/log(10)) is the number of decimal digits in p. - Max Alekseyev
There is no prime p such that p^2 divides p.p.
All primes of the forms 10^(2m) - 10^m + 1 or (1/3)*(10^(2m) + 10^m + 1) are in the sequence.
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LINKS
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CROSSREFS
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KEYWORD
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nonn,base,more
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AUTHOR
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STATUS
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approved
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