|
|
A144721
|
|
a(0) = 2, a(1) = 5, a(n) = 4 * a(n-1) - a(n-2).
|
|
3
|
|
|
2, 5, 18, 67, 250, 933, 3482, 12995, 48498, 180997, 675490, 2520963, 9408362, 35112485, 131041578, 489053827, 1825173730, 6811641093, 25421390642, 94873921475, 354074295258, 1321423259557, 4931618742970, 18405051712323, 68688588106322, 256349300712965
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,1
|
|
COMMENTS
|
For all members x of the sequence, 3*x^2 - 11 is a square. - Sture Sjöstedt, Nov 30 2011
|
|
LINKS
|
|
|
FORMULA
|
Sequence satisfies -11 = f(a(n), a(n+1)) where f(u, v) = u^2 + v^2 - 4*u*v.
G.f.: (2 - 3*x) / (1 - 4*x + x^2). a(n) = (11 + a(n-1)^2) / a(n-2).
a(n) = ((2-sqrt(3))^n*(-1+2*sqrt(3))+(2+sqrt(3))^n*(1+2*sqrt(3)))/(2*sqrt(3)). - Colin Barker, Oct 12 2015
|
|
MATHEMATICA
|
a[0] := 2; a[1] := 5; a[n_] := a[n] = 4a[n - 1] - a[n - 2]; Table[a[n], {n, 0, 24}] (* Alonso del Arte, Nov 30 2011 *)
|
|
PROG
|
(PARI) {a(n) = real( (2 + quadgen(12))^n * ( 2 + 1 / quadgen(12) ))}
(PARI) {a(n) = subst( (4*polchebyshev(n) + polchebyshev(n-1)) / 3, x, 2)}
(Magma) I:=[2, 5]; [n le 2 select I[n] else 4*Self(n-1)-Self(n-2): n in [1..30]]; // Vincenzo Librandi, Jun 06 2015
(PARI) Vec((2-3*x)/(1-4*x+x^2) + O(x^40)) \\ Colin Barker, Oct 12 2015
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|