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%I #2 Oct 01 2013 18:06:44
%S 1,16,350,7504,161593,3481214,75000049,1615826124,34811916483,
%T 750000000499
%N Floor of sum of the first 10^n cube roots.
%C Conjecture: For n = 3k, a(n) = (3/4)*10^(4n/3)+5*10^(n/3-1)-1.
%e For n = 6, a(6) = (3/4)*10^8 + 5* 10^1-1 = 75000049.
%o (PARI) /* For this sequence, p = 3 */ g2(n,p) = for(j=0,n,s=0;for(x=0,10^j,s+=x^(1/p));print1(floor(s)","))
%K nonn
%O 0,2
%A _Cino Hilliard_, Mar 19 2008
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