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A135937
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a(1)=1; for n>=2, a(n) = Product_{d|a(n-1)} (d+1), where the product is over all positive divisors d of a(n-1).
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1
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OFFSET
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1,2
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COMMENTS
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The next term is a lot bigger than 70000! and is too large to include. - Stefan Steinerberger, Dec 31 2007
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LINKS
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EXAMPLE
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The positive divisors of a(3)=6 are 1,2,3,6. So a(4) = (1+1)*(2+1)*(3+1)*(6+1) = 2*3*4*7 = 168.
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MATHEMATICA
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a = {1}; Do[AppendTo[a, Times @@ (Divisors[a[[ -1]]] + 1)], {4}]; a (* Stefan Steinerberger, Dec 31 2007 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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