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A134097
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a(n) = 2^[n(n+1) - A000120(n)] * [x^n] 1/(1-x)^(1/2^n) for n>=0, where A000120(n) = number of 1's in binary expansion of n.
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2
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1, 1, 5, 51, 9163, 1789359, 2966784613, 10246481110899, 1164644624885859315, 67519816893223600328475, 31778915061906077887063371935, 30252957250679839624103772879830589
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OFFSET
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0,3
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COMMENTS
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[x^n] 1/(1-x)^(1/2^n) denotes the coefficient of x^n in the (2^n)-root of 1/(1-x).
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LINKS
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PROG
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(PARI) {a(n)=polcoeff(1/(1-x+x*O(x^n))^(1/2^n), n)*2^(n*(n+1)-subst(Pol(binary(n)), x, 1))}
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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