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A131528 a(n) = (n^1 + 1!)*(n^2 + 2!)*(n^3 + 3!)*(n^4 + 4!)/2!. 2

%I #4 Mar 31 2012 20:08:02

%S 144,525,5040,76230,882000,6886539,38974320,172650300,633845520,

%T 2008589625,5657204784,14470043490,34161950160,75378387735,

%U 156979350000,310979592504,589757174160,1076298622245,1898430030000,3248190882750,5407743199824,8783474489955

%N a(n) = (n^1 + 1!)*(n^2 + 2!)*(n^3 + 3!)*(n^4 + 4!)/2!.

%C Comment from Peter J. C. Moses, Aug 29 2007: the values of m = m(k) needed to make the sequence a(n,k) = m (n^1 + 1!) (n^2 + 2!) ... (n^i + k!) / k! (n >= 0) take integral values for all n are given in A049614.

%H T. D. Noe, <a href="/A131528/b131528.txt">Table of n, a(n) for n = 0..1000</a>

%F G.f.: (-3*(48 + x*(-353 + x*(2395 + x*(8635 + x*(93855 + x*(217437 + x*(213873 + 5*x*(12325 + x*(1441 + 16*x)))))))))) / (x - 1)^11 - Peter J. C. Moses, Aug 29 2007

%K nonn

%O 0,1

%A _Alexander R. Povolotsky_, Aug 25 2007

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