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%I #17 Mar 17 2019 02:04:23
%S 1,2,4,4,8,4,8,8,16,4,8,8,16,8,16,16,32,4,8,8,16,8,16,16,32,8,16,16,
%T 32,16,32,32,64,4,8,8,16,8,16,16,32,8,16,16,32,16,32,32,64,8,16,16,32,
%U 16,32,32,64,16,32,32,64,32,64,64,128,4,8,8,16,8,16,16,32,8,16,16
%N Denominator of (exponential) expansion of log((x/2-1)/(x-1)).
%C a(n+1) = 2^A063787(n). a(n+1) = A001316(n)/2. - _Stephen Crowley_, Aug 25 2008
%C Also, 1 followed by A117973. - _Omar E. Pol_, Dec 11 2010
%F a(n) = 0^n + n + Sum_{k=0..n-1} (-1)^(1 + binomial(n-1,k)). - _Stephen Crowley_, Aug 25 2008
%e From _Omar E. Pol_, Jun 14 2009, Dec 11 2010: (Start)
%e May be written as a triangle by using the Crowley formula with A063787:
%e .1;
%e .2;
%e .4,4;
%e .8,4,8,8;
%e .16,4,8,8,16,8,16,16;
%e .32,4,8,8,16,8,16,16,32,8,16,16,32,16,32,32;
%e .64,4,8,8,16,8,16,16,32,8,16,16,32,16,32,32,64,8,16,16,32,16,32,32,64,16,...
%e Also
%e 1,
%e 2,
%e 4,
%e 4,8,
%e 4,8,8,16,
%e 4,8,8,16,8,16,16,32,
%e 4,8,8,16,8,16,16,32,8,16,16,32,16,32,32,64,
%e 4,8,8,16,8,16,16,32,8,16,16,32,16,32,32,64,8,16,16,32,16,32,32,64,16,32,...
%e (End)
%p a(n)=abs(op(1, numer(expand(Zeta(2n)/Zeta(1-2n))))) # _Stephen Crowley_, Aug 25 2008
%t With[{nn=80},Denominator[CoefficientList[Series[Log[(x/2-1)/(x-1)],{x,0,nn}],x] Range[0,nn]!]] (* _Harvey P. Dale_, Apr 28 2016 *)
%Y Cf. A001316, A131135.
%Y Cf. A063787.
%Y Cf. A000079, A117973. - _Omar E. Pol_, Jun 14 2009, Dec 11 2010
%K nonn
%O 0,2
%A _Paul Barry_, Jun 17 2007
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